A nonzero row or column
A leading entry of row
: the leftmost nonzero entry
※ entry: values in matrix
Echelon Forms
- All nonzero rows are above any row of all zeros.
- Each leading entry of a row is in a column to the right of the leading entry of the row above it
Reduced echelon forms
- The leading entry in each nonzero row is 1.
- Each leading 1 is the only non zero entry in its column.
Theorem 1. Uniqueness of the Reduced Echelon Forms
Each matrix is row equivalent to one and only one reduced echelon matrix.
→ matrix를 row reduction을 통해 reduced echelon form을 만들게 되면, 해당 reduced echelon form의 형태를 제외한 다른 reduced echelon form은 나올 수 없다.
Row Reduction Algorithm
step 1) begin with the leftmost nonzero column.
step 2) select a nonzero entry in the pivot column as a pivot. If necessary, interchange rows to move this entry into the pivot postion.
step 3) row replacement to create zeros in all positions below the pivot.
step 4) apply steps 1-3 to the submatrix that remain.
※ The combination of steps 1-4 is called fowrad phase → echelon form
step 5) beginning with the rightmost pivot and working upward and to the left, create zeros above each pivot. If a pivot is not 1, make it 1 by a scaling operation.
※ Step 5 is called backward phase → reduced echelon form
solution of linear systems
Ex 1. Find the general solution of the following augmented matrix.
$$ \left[ \begin{matrix} 1 & 6 & 2 & -5 & -2 & 4 \\ 0 & 0 & 2 & -8 & -1 & 3 \\ 0 & 0 & 0 & 0 & 1 & 7 \\ \end{matrix} \right] $$
Sol)
Theorem 2. Exsistence and Uniquness Theorem
A linear system is consistent if and only if the rightmost column of hte augmented matrix is not a pivot column- that is, if and only if an echelon form of the augmented matrix has no row of the forms
$$ \left[ \begin{matrix} 0 & 0 & ... & b \end{matrix} \right] $$
$$b\;is \; nonzero$$
If a linear system is consistent, then the solution set contains either
- a unique solution, when there are no free variables
- or infinitely many solutions, when there is at least one free variables
※ Reference
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